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mote1985 [20]
3 years ago
10

Hello can you please help me posted picture of question

Mathematics
2 answers:
algol133 years ago
8 0
The sum of probabilities of all outcomes of a sample space always equal to 1.

Probability of picking yellow candy = 1 - Probability of picking any of the other candy

P (Not yellow) = 0.13 + 0.20 + 0.16 + 0.24 + 0.13 
P Not yellow) = 0.86

P(Yellow) = 1- P(not yellow)

= 1- 0.86

P(Yellow) = 0.14

Therefore, the correct answer is option C
Lostsunrise [7]3 years ago
7 0
It would be C. 0.14. You add together the rest of the decimals which gets you 0.86 and subtract them from 100, 
You might be interested in
T(z)= sin^2(z/4), {-3 ≤ z ≤ 8}
Usimov [2.4K]

Answer:

T´(z)=n^2s/4*i

Step-by-step explanation:

T(z)=d/dz(sin^2*z/4)

T´(z)=d/dz(sn^2zi/4)

T´(z)=d/dz(sn^2z/4*i)

T´(z)i*d/dz(sn^2z/4)

T´(z)=n^2s/4*i

Simplify

3 0
3 years ago
HELP PLEASE: Which is the equation of the graphed line written in
maksim [4K]

Answer:

x - y = 0

Step-by-step explanation:

Required

The graph equation

From the graph, we have:

(x_1,y_1) = (0,0)

(x_2,y_2) = (1,1)

The slope of the graph is:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{1-0}{1-0}

m = \frac{1}{1}

m =1

So, the graph equation is:

y = m(x - x_1) + y_1

y = 1 * (x - 0) + 0

y = 1 * x

y = x

In standard form, we have:

x - y = 0

6 0
3 years ago
Write a paragraph proof.
worty [1.4K]
It is given that line segment BC is congruent to line segment EC and that line segment AC is congruent to DC. Because of the vertical angles theorem, angle BCA is equal to angle DCE. Therefore, triangles CBA AND DEC are congruent by SAS. Using CPCTC, BA is equal to ED.
8 0
3 years ago
Directions: Using the digits 1 to 9, at most one time each, fill in the boxes to find the largest or smallest possible values fo
12345 [234]

9514 1404 393

Answer:

  smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

  largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

  • ax -b = c
  • dy +e = f

Then the values of x and y are ...

  x = (c +b)/a

  y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

<h3>Smallest sum</h3>

For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

  • 8x -3 = 4   ⇒   x = 7/8
  • 1y +9 = 2   ⇒   y = -7

For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

<h3>Largest sum</h3>

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

  • 1x -9 = 8  ⇒   x = 17
  • 2y +3 = 7   ⇒   y = 2

For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

<em>Additional comment</em>

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0
3 years ago
Read 2 more answers
Let T: Mmxn(R)Mmxn(R) be the function defined
alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors x,y \in V and for all scalars c \in R. And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: M_{mxn} (R) > M_{nxm} (R)

Where T(A) = A^T

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)

And we can express like this T(A+B) =T(A) + T(B)

3) If A \in M_{mxn}(R) and c \in R then we have this:

T(cA) = (cA)^T = cA^T = cT(A)

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

5 0
3 years ago
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