G(x) =x^4+x^3+4x^2+4x

Mathematics

1 answer:

weeeeeb [17]2 years ago

4 0

Answer:

$g(x) = x {}^{4} + x {}^{3} + 4x {}^{2} + 4x \\ 0 =x {}^{4} + x {}^{3} + 4x {}^{2} + 4x \\ x {}^{4} + x {}^{3} + 4x {}^{2} + 4x = 0 \\ x {}^{3} \times (x + 1) + 4x \times (x + 1) = 0 \\ x \times (x + 1) \times (x {}^{2} + 4) = 0 \\ x = 0 \\ x + 1 = 0 \\ x { }^{2} + 4 = 0 \\ \\ x \frac{}{1} = - 1 \\ x \frac{}{2} = 0$

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