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Mumz [18]
3 years ago
12

G(x) =x^4+x^3+4x^2+4x

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

g(x) = x {}^{4}  + x {}^{3}  + 4x {}^{2}  + 4x \\ 0 =x {}^{4}  + x {}^{3}  + 4x {}^{2}  + 4x \\ x {}^{4}  + x {}^{3}  + 4x {}^{2}  + 4x = 0 \\ x {}^{3}  \times (x + 1) + 4x \times (x + 1) = 0 \\ x \times (x + 1) \times (x {}^{2}  + 4) = 0 \\ x = 0 \\ x + 1 = 0 \\ x { }^{2}  + 4 = 0 \\  \\ x  \frac{}{1}    =  - 1 \\ x  \frac{}{2} =  0

HOPE IT HELPS YA MATE!.please give me brainliest.

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<em><u>Solution:</u></em>

Given that,

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