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zavuch27 [327]
3 years ago
14

Will give 5 starts, thanks need this FAST!!!!!!!!!!!!!!!

Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer: i dont know how exact you want it but the answer is 31.4159265359

Step-by-step explanation: you have to double the raduis and multiple buy pie.

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20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that
IRINA_888 [86]

<u>ANSWER:  </u>

The algebraic expression for number of ribbons is \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into 7\frac{1}{2} inches or 6\frac{3}{4} inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}

\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right ]

So, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}

So, the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

Hence, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

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How do i factor x^3+3x^2
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All you need to do is pull out the common factor of x^2:
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A drainage pipe 66 in. tall measures 25.12 in. around.
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In order to solve this using V= B(h) (The B is area of the base) you need a radius it doesn't give us that but it does give us the circumference. 
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