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navik [9.2K]
4 years ago
14

Simplify:9(8a+b) + 2(a+b)

Mathematics
1 answer:
Viktor [21]4 years ago
4 0
The answer is going to be 74a+11b

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Determine whether each of these sets is countable oruncountable. For those that are countably infinite, exhibit
mezya [45]

Answer:

Answers are given below.

Step-by-step explanation:

a) one-to-one correspondence between the set of positiveintegers and that set.

Whenever we have one to one correspondence with positive integers, the set is countable and here infinite.

b) integers divisible by 5 and not 7 ..This set is all integers divisible by 5 but not by 7.  This is a discrete set and hence countable and infinite.

c) the real numbers with decimal representationsconsisting of all 1’s

-- This cannot be counted and hence uncountable but infinite.

d) the real numbers with decimal representationsconsisting of all 1’s or 9’s

-- This is also uncountable but infinite.

6 0
3 years ago
Find the midpoint of the segment with the endpoints (-2,-6) and (8,8)
Usimov [2.4K]

Answer:

(3,7)

Step-by-step explanation:

no time thank you

7 0
3 years ago
This is very very simple
Advocard [28]

Answer:

2

Step-by-step explanation:

2+2+4=8/4=2

8 0
3 years ago
Read 2 more answers
Write the following expression as a fraction in lowest terms:
alukav5142 [94]

Step-by-step explanation:

\[2 + \cfrac{2}{2 + \cfrac{3}{3 + \cfrac{4}{4 + 5}}}\]=

\[2 + \cfrac{2}{2 + \cfrac{3}{3 + \cfrac{4}{9}}}\]=

\[2 + \cfrac{2}{2 + \cfrac{3}{\cfrac{31}{9}}}\]=

\[2 + \cfrac{2}{2 + \cfrac{27}{31} }}}\]=

\[2 + \cfrac{2}{ \cfrac{62+27}{31} }}}\]=

\[2 + \cfrac{2}{ \cfrac{89}{31} }}}\]=

\[2 + \cfrac{62}{{89} }}}\]=

\[2  \cfrac{62}{{89} }}}\]

3 0
2 years ago
Read 2 more answers
So can someone explain how the heck does 4 x 4 x 4 = 64??
sweet-ann [11.9K]

Answer:

it is more like, 4x4=16

16x4=64

Step-by-step explanation:

I know it can be confusing, but you will eventually get it :)

i think you were adding 4+4+4=12, but that is not what you are supposed to do here.

Hope i helped :)

5 0
2 years ago
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