All categories

3 years ago

A cube has a side length of 5xcm. What is the volume of the cube?no links please.

Mathematics

1 answer:

finlep [7]3 years ago

7 0

Answer:

125 cm

Step-by-step explanation:

$V=lwh$

all cube has the same length, width, height

5 * 5 * 5 = 125

Hope this helps

You might be interested in

Y=6x+13 x-intercept and y-intercept

Nonamiya [84]

Answer:

y int (0, 13)

x int (-13/6,0)

just make the x = 0 and solve to get y

same with the x make y =0 and solve

3 0

2 years ago

Suppose a South Korean inspirational speaker speaks from a rectangular stage measuring 30 feet by 70 feet. Find the area of the

OleMash [197]

The area of a rectangle is calculated my multiplying the length of the rectangle and the width of the rectangle. In this case, the length (the longer side) is 70 feet while the width (shorter side) is 30 feet. Hence the area is 2,100 ft2.

4 0

2 years ago

3125x=−62 value of x.

Papessa [141]

Answer:

x= -0.01984

Step-by-step explanation:

You divide both sides by 3125 to get x alone.

You get x=-0.01984

Hope this helps!

5 0

2 years ago

Which table represents a linear function?

katrin [286]

Answer:

Option A

Step-by-step explanation:

the y value has a constant slope of 5 while the other tables have changing slopes

6 0

2 years ago

Read 2 more answers

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):