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scoundrel [369]
3 years ago
8

Micah deposits C dollars in a bank. The deposited amount earns an annual interest rate of r% and becomes D dollars in t years ac

cording to the formula Which formulas could be used to calculate t given C,D, and r
Mathematics
2 answers:
vovangra [49]3 years ago
7 0

Answer:

t = \frac{100}{r} [\frac{D}{C} - 1]

Step-by-step explanation:

Assume that the deposited amount C dollars earn r% simple interest annually.

If after t years the deposited amount C dollars grows to D dollars, then we are asked to write a relation using the given terms to calculate t.

Now, using the formula of simple interest we can write

D = C(1 + \frac{t\times r}{100})

⇒ 1 + \frac{t \times r}{100} = \frac{D}{C}

⇒ \frac{t \times r}{100} = \frac{D}{C} - 1

⇒ t = \frac{100}{r} [\frac{D}{C} - 1]

So, this is the expression for t. (Answer)

Yuri [45]3 years ago
5 0

Answer:

t= 100/r [d/c-1]

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Let U be the 3 2 matrix [0.45 0.42, 0.25 0.35, 0.15 0.15]. The first column of U lists the costs per dollar of output for manufa
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C. The 4 columns of UQ list the total costs for materials, labor, and overhead used to manufacture products B and C during the 4 quarters of the year.

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U=\left\begin{array}{ccc}\\$Cost of Materials\\ $Cost of Labour\\ $Cost of Overhead\end{array}\right\left(\begin{array}{cc}$Product B&$Product C\\0.45&0.42\\ 0.25&0.35\\ 0.15&0.15\end{array}\right)

q_1 is a vector in the set of real numbers R^2 that lists the output​ (measured in​ dollars) of products B and C manufactured during the first quarter of the​ year.

Therefore:

UQ=\left\begin{array}{ccc}\\$Cost of Materials\\ $Cost of Labour\\ $Cost of Overhead\end{array}\right\left(\begin{array}{cc}$Product B&$Product C\\0.45&0.42\\ 0.25&0.35\\ 0.15&0.15\end{array}\right)\left(\begin{array}{ccc}q_{1B}\\q_{1C}\end{array}\right)\left(\begin{array}{ccc}q_{2B}\\q_{2C}\end{array}\right)\left(\begin{array}{ccc}q_{3B}\\q_{3C}\end{array}\right)\left(\begin{array}{ccc}q_{4B}\\q_{4C}\end{array}\right)

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The 4 columns of UQ list the total costs for materials(Row 1), labor(Row 2), and overhead(Row 3) used to manufacture products B and C during the 4 quarters of the year.

3 0
3 years ago
3/5n+15=10+2/5n what is n
Nutka1998 [239]

\textsf{Hey there!}

\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}

\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}

\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}

\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}

\textsf{Solve\ the set we have left over}

\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}

\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}

\mathsf{\dfrac{1}{5}n+15-15=10-15}

\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }

\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }

\mathsf{10-15=-5}

\mathsf{New\ equation: \dfrac{1}{5}n=-5}

\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}

\mathsf{\dfrac{1}{5}n\times5=5\times-5}

\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \  it \ gives \ us \ 1}\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}

\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}

\textsf{Thus, \underline{\bf{n = -25}}}\checkmark

\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

7 0
3 years ago
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