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3 years ago

How much she makes per hour

Mathematics

2 answers:

Luda [366]3 years ago

7 0

90÷5=18 which means she makes $18 every hour.

Answer= $18

Harman [31]3 years ago

5 0

Answer:

18$

Step-by-step explanation:

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Find the 4 digit code btw its not 5396 or 6935

Sergeeva-Olga [200]

I think it would be 3569 , i’m not sure tho.

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2 years ago

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Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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2 years ago

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Can some one please help me ???!

Sedaia [141]

45 = 3x3x5
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3 years ago

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What is the limit as x is approaching 0 of the absolute value of x

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Recall that, an absolute value expression is a piece-wise in effect, thus we'd check the single-sided limits,

$\bf \lim\limits_{x\to 0}~|x|\implies 
\begin{cases}
\lim\limits_{x\to 0^-}~-x\\\\
\lim\limits_{x\to 0^+}~+x
\end{cases}\implies 
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0\\\\
0
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3 years ago

For a 4-unit class like Statistics, students should spend average of 12 hours studying for the class. A survey was done on 24 st

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Answer:

a) 68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 13 hours

Standard deviation = 2.8 hours.

a) 68% of the students spend between hours and hours on Statistics each week.

Within 1 standard deviation of the mean.

13 - 2.8 = 10.2 hours

13 + 2.8 = 15.8 hours

68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between hours and hours on Statistics each week.

Within 2 standard deviations of the mean

13 - 2*2.8 = 7.4 hours

13 + 2*2.8 = 18.6 hours

95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between hours and hours on Statistics each week.

Within 3 standard deviations of the mean

13 - 3*2.8 = 4.6 hours

13 + 3*2.8 = 21.4 hours

99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

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2 years ago