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aev [14]
3 years ago
13

In a condominium complex, 2/3 of the women are married to 3/4 of the women. What part of the entire population is married? Pleas

e show work
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

(QUESTION CORRECTNESS : 2/3 OF MEN ARE MARRIED TO 3/4 OF WOMEN)

Part of Entire Population married = 12/17 = 70.58%

Step-by-step explanation:

Fraction of men married:

\frac{2}{3}=\frac{4}{6}=\frac{6}{9}=\frac{8}{12}..........

Fraction of women married:

\frac{3}{4}=\frac{6}{8}=\frac{9}{12}=\frac{12}{16} .........

To solve the problem, we know that number of husbands should be equal to number of wives.

Number of husbands and wives are represented by the numerators of both fractions.

We have to find such a multiple of each fraction such that there numerator are same.

Let fraction of men married:  \frac{6}{9}

Let fraction of women married:  \frac{6}{8}

Add the numerators and denominator to find the solution:

\frac{6+6}{9+8}= \frac{12}{17}

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A telephone pole has a wire attached to its top that is anchored to the ground. the distance from the bottom of the pole to the
kirza4 [7]

The height of the pole is 96 feet

In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation relating the lengths of the legs a, b and the hypotenuse c, often called the Pythagorean equation:[1]

a^{2}+b^{2}=c^{2},

Create a diagram of the scenario first. You would have a right triangle with a hypotenuse (longest side) of h + 4, a longest leg of h - 68, and one leg of length h to represent the pole.

Set up the equation h^2 + (h - 68)^2 = (h + 4)^2 using the Pythagorean theorem (a^2 + b^2 = c^2).

h^2 + (h - 68)^2 = (h + 4)^2

On simplifying we get

h^2+h^2-136h+4624 = h^2+8h+16

2h^2-136h+4624=h^2+8h+16

h^2-144h+4608=0

Solving using quadratic formula

h_{1,\:2}=\frac{-\left(-144\right)\pm \sqrt{\left(-144\right)^2-4\cdot \:1\cdot \:4608}}{2\cdot \:1}  

h_1=\frac{-\left(-144\right)+48}{2\cdot \:1},\:h_2=\frac{-\left(-144\right)-48}{2\cdot \:1}

h1 = 96 feet , h2 = 48 feet

If height would have been 48 feet then the other side would have a negative value as as 48 - 68 = -20 .

Hence the height of the pole is 96 feet

Learn more about Pythagoras theorem here :

brainly.com/question/343682

#SPJ4

7 0
1 year ago
Point C ∈ AB , AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.
Shtirlitz [24]

let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.


\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}}
\\\\\\
AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x
\\\\\\
\cfrac{30}{2.5}=x\implies 12=x
\\\\[-0.35em]
~\dotfill\\\\
AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12

8 0
3 years ago
If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they
nikklg [1K]

Answer:

9\dfrac{1}{4}

4\dfrac{5}{8}

Step-by-step explanation:

The master chief has three and a half cookies i.e. 3\dfrac{1}{2} = \dfrac{7}{2} numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. 5\dfrac{3}{4} = \dfrac{23}{4} number of cookies.

Therefore, in total there are (\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4} numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get \dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8} numbers of cookies. (Answer)  

3 0
3 years ago
What is 110% of 90 as a fraction
Vlad1618 [11]
110% of 90 is:
90*1.10 = 99

5 0
2 years ago
Read 2 more answers
For the following exercises, evaluate the function f at the values f(−2), f(−1), f(0), f(1), and f(2)
MatroZZZ [7]

Answer:

See below.  <u><em>I assume that (x) = 8x2 - 7x + 3 is really (x) = 8x^2 - 7x + 3</em></u>

Step-by-step explanation:

Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3

For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3.  f(0) = 3

f(-2) would be f(-2) = 8(-2)^2 - 7(-2) + 3.  

                                =   8*4  + 14 +3

                                = 32 + 17        therefore      f(-2) = 49

<u>x</u> <u>f(x)</u>

-2 49

-1 18

0 3

1 4

2 21

4 0
2 years ago
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