Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
Grace
Step-by-step explanation:
We have to look at the bottom 2 angles, the bigger the angle the wider it is. For Hector, his R angle is 50 degrees and it's 14 wide, but his R angle is 60 degrees, bigger than 50 degrees, and yet the it's only 12.5 wide which is smaller than 14. Grace got it right, 60 degrees is bigger than 50 so it's only natural for it to be wider too.
I believe it is 510 cm because a meter equals 100 cm so 210 cm times 2 equals 410 cm then multiply 45 times 2 and get 90 cm then add 410 plus 90 and get 510 cm.
Equation:
y + 2 = 1/3(x+1)
Assuming you are solving for Y:
y + 2 = 1/3(x) + 1/3(1)
(y + 2) - 2 = (1/3x + 1/3) - 2
y = 1/3x + 1/3 - 2
<u>y = 1/3x - 5/3</u>