All categories

2 years ago

Find the midpoint M of the two sets of points. (Use midpt. formula)

Mathematics

1 answer:

Setler79 [48]2 years ago

5 0

3.5,1.75
7/2,3.5/2
Those 2

You might be interested in

Which sets of ordered pairs show equivalent ratios? Check all that apply.

julsineya [31]

Answer:

Step-by-step explanation:

Can I have brainilest plz

7 0

2 years ago

Solve.<br><br>(Sorry About my handwriting)<br>

Varvara68 [4.7K]

Answer: the answer is gonna be a decimal which is Decimal: 145.333333 the 3 is repeated it keeps going forever

7 0

2 years ago

Which is an equation in point-slope form for the given point and slope?

xxMikexx [17]

Hi There!

Solution,

Point Slope Form: y - y1 = m(x - x1)

Now you have a reference equation of what the answer should look like.

By looking at the answer choices you can eliminate A.

Tip: When you have a negative number you are going to add. For Example, if you have -8, you will input x + 8 or y + 8.

Tip 2: When you have a positive number you are going to subtract. For Example, if you have 3 you will input x - 3 or y - 3.

We can eliminate B because its not subtracting 3.

We can also eliminate C because its not adding -8.

The best answer choice is D.

Answer,

y – 3 = 6(x + 8)

I hope you understand, so you can do this in the future on your own.

Hope This Helps :)

4 0

3 years ago

Please help me with this

satela [25.4K]

Area of the trapezoid:
$\frac{12.8 + 4.2}{2} (4.9) = 41.65 cm^2$

Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2

Area of each quarter circle:
$\frac{ \pi (3.1)^{2} }{4} = 7.54 cm^2$

We have two quarter circles:
7.54 + 7.54 = 15.08

41.65 + 13.02 + 15.08 = 69.75 cm^2

5 0

2 years ago

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be

lions [1.4K]

Answer:

0.8213

Step-by-step explanation:

-This is a binomial probability problem given by the function:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}$

Given that n=21 and p=0.2, the probability that she experience a delay on at least 3 days is calculated as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X$

Hence, the probability that she experience delay on at least 3 days is 0.8213

6 0

3 years ago