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3 years ago

Which best describes the orthocenter of a triangle

Mathematics

2 answers:

Gnom [1K]3 years ago

8 0

The point of intersection of all 3 altitudes

inna [77]3 years ago

5 0

the point where the three altitudes of the triangle intersect

You might be interested in

Mariana wears her winter coat when the temperature is colder than -4^{\circ}\text{C}−4 ∘ Cminus, 4, degrees, start text, C, end

Savatey [412]

Answer:

T < - 4°C

Step-by-step explanation:

Given that Mariana wears her coat only when temperature is colder than - 4°C

Recall that lower temperature values indicate higher degree of coldness ;

Hence, Mariana will only wear her coat when temperature values are lesser than - 4°C ; this means that the temperature at that period is colder than - 4°C.

Hence, the inequality expression which is only true for temperatures when Mariana wears her coat can be written as :

Temperature = T

T < - 4°C

5 0

3 years ago

Read 2 more answers

Plz help me with this

blsea [12.9K]

Answer:

I really don't know but this is a bad guess 11 inches but don't hold me accountable

3 0

3 years ago

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

Naddika [18.5K]

Answer:

Using a 90% confidence level

A. A sample size of 68 should be used.

B. A sample size of 98 should be used.

Step-by-step explanation:

I think there was a small typing mistake and the confidence level was left out. I will use a 90% confidence level.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used?

We have the standard deviation in minutes, so the margin of error should be in minutes.

72 seconds is 72/60 = 1.2 minutes.

So we need a sample size of n, and n is found when M = 1.2. We have that $\sigma = 6$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1.2 = 1.645*\frac{6}{\sqrt{n}}$

$1.2\sqrt{n} = 6*1.645$

$\sqrt{n} = \frac{6*1.645}{1.2}$

$(\sqrt{n})^{2} = (\frac{6*1.645}{1.2})^{2}$

$n = 67.65$

Rounding up.

A sample size of 68 should be used.

B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Same logic as above, just use M = 1.

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.645*\frac{6}{\sqrt{n}}$

$\sqrt{n} = 6*1.645$

$(\sqrt{n})^{2} = (6*1.645)^2$

$n = 97.42$

Rounding up

A sample size of 98 should be used.

3 0

3 years ago

Don tracked the price of gas for several months. In January gas cost $2.65, in February the price had risen $0.56, in March decr

Elan Coil [88]

Starting price is 2.65, increased by .56

2.65+.56=3.21

Price is 3.21, decreased by .23

3.21-.23=2.98

Price is 2.98, increased by 1.02

2.98+1.02= 4

Price is 4, decreased by .48

4-.48=3.52

Now find the difference from the starting price (January) from the end price (May)

3.52-2.65=.87

<u>The difference from gas prices is $.87</u>

8 0

4 years ago

A professional basketball court is in the shape of a rectangle. It is 50 feet wide and 94 feet long. A player runs one time arou

goldfiish [28.3K]

It's the perimeter

50+50+*94+94 =

288 feet

5 0

3 years ago