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Monica [59]
4 years ago
10

What is the equation of the line that goes through (3,11) and is parallel to the line 2x-y=5

Mathematics
1 answer:
Strike441 [17]4 years ago
3 0
The equation is y=2x+5
why?
2x-y=5
y=2x-5
from here we can find the slope, which is 2, and we know that parallel lines have equal slopes
 the standard form of eq of line is y=mx+b
substitute y and x with the numbers from ordinate pair (3,11):
11=3*2+b
6+b=11
b=5
Now you can write the eq of line:
y=2x+5
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alekssr [168]

Answer:

28 inches

Step-by-step explanation:

28×22/7×28

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7 0
3 years ago
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Which of the following graphs best represents the solution to the pair of equations below? y = −x + 6 y = 2x − 3 A coordinate pl
Lera25 [3.4K]
The lines are 

i)  y=-x+6
ii) y=2x-3

The solution of the system of equations is found by equalizing the 2 equations:

-x+6=2x-3

-2x-x=-6-3

-3x=-9

x=-9/(-3)=3

substitute x=3 in either i) or ii):

i)  y=-3+6=3
ii) y=2(3)-3=6-3=3

(the result is the same, so checking one is enough)

This means that the point (3, 3) is a point which is in both lines, so a solution to the system.

In graphs, this means that the lines intersect at (3, 3) ONLY


Answer: The graph where the lines intersect at (3, 3)
3 0
4 years ago
Paul travel to the lake and back. The trip took 3 hours and the trip back took 4 hours He averaged 10 mph faster on the trip the
ollegr [7]

Answer:

  40 mph

Step-by-step explanation:

We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...

  outbound speed : inbound speed = 4 : 3

These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...

  4×10 mph = 40 mph

Paul's average speed on the outbound trip was 40 mph.

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The distance to the lake was 120 mi.

4 0
3 years ago
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A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi
inessss [21]

Answer:

\frac{1429}{120} or 11\frac{109}{120}

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)

x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)

x = \frac{1}{120}(40+30+24+15+840)

x = \frac{1}{120}(949)

x = \frac{949}{120}

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = \frac{949}{120}+4

Original number of peaches = \frac{949+4\times 120}{120}

Original number of peaches = \frac{949+480}{120}

Original number of peaches = \frac{1429}{120}

Original number of peaches = 11\frac{109}{120}

Therefore the original number of peaches in the basket is \frac{1429}{120} or 11\frac{109}{120}

5 0
3 years ago
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Lera25 [3.4K]

Answer:

2xy^2


Step-by-step explanation:

The question is:

\frac{6x^{2}y^3}{3xy}


<em>"6" and "3" cancels out as well as the "x"s and "y"s. Shown below</em>:

\frac{6x^{2}y^3}{3xy}\\=2xy^2

4 0
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