Answer:
- 12 ft parallel to the river
- 6 ft perpendicular to the river
Step-by-step explanation:
The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.
72 = W(2W)
36 = W²
6 = W . . . . . . the width perpendicular to the river
12 = 2W . . . . the length parallel to the river
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<em>Development of this relation</em>
Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...
A = xy = x(T -x)/2
Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...
x = (0 +T)/2 = T/2
The corresponding area width (y) is ...
y = (T -T/2)/2 = T/4
Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.
Answer:
b=-5
Step-by-step explanation:
Divide by -9 to eliminate the -9 on -9b
(Since -9b is the same thing as -9 times b we can use the inverse of multiplication which is division to eliminate the -9 from b but we need to do it on both sides to make it balance)
-9b/-9=45/-9
b=-5
If R is the midpoint of PS, then PR = RS -- (1)
Also, PR + RS = PS -- (2)
__________________
PR + RS = PS
7x + 23 + 13x - 19 = PS
__________________
Now, PR = PS
7x + 23 = 13x - 19
7x - 13x = -19 - 23
-6x = -42
x = -42/-6
x = 7
__________________
PS = 7x + 23 + 13x - 19
PS = 7(7) + 23 + 13(7) - 19
PS = 49 + 23 + 91 - 19
<u>PS </u><u>=</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u>
Hope it helps!
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
Answer:
The answer would be D or 8 bc 8x1=8 8x2=16 and that would be the GCF.
Step-by-step explanation:
Answer:
452.39 mi^2
Step-by-step explanation:
A = πr^2
A = π (12mi)^2
A = 452.39 mi^2
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