Answer:
I = 4.38 x 10⁻⁷ A
Explanation:
Given,
speed = 4.47 x 10⁴ m/s
radius of the circular path, r = 2.59 x 10⁻⁹ m
effective current = ?
The current represented by the orbiting electron is equal to
f is the frequency
q is charge of electron
we know,
f = 2.74 x 10¹² Hz
now,
I = 4.38 x 10⁻⁷ A
Hence, the effective current associated with the orbiting electron is equal to I = 4.38 x 10⁻⁷ A
Answer:
The solved problems are in the photos. Hope it helps.
<u>Answer:</u> The velocity of the 2.2 kg block is 5.23 m/s
<u>Explanation:</u>
To calculate the velocity of the 2.2 kg block after the collision, we use the equation of law of conservation of momentum, which is:
where,
= mass of block 1 = 5 kg
= Initial velocity of block 1 = 2.3 m/s
= Final velocity of block 1 = 0 m/s
= mass of block 2 = 2.2 kg
= Initial velocity of block 2 = 0 m/s
= Final velocity of block 2 = ?
Putting values in above equation, we get:
Hence, the velocity of the 2.2 kg block is 5.23 m/s
Answer:
3 m/s
Explanation:
The computation of speed is shown below:-
We will compute the equation by using the law of conservation of momentum; also, the total momentum prior and following the collision must be conserved. Therefore we can write the equation is the following manner:-
where the symbols represent
150 kg is the mass of spaceship 1 = m1
150 kg is the mass of spaceship 2 = m2
0 m/s is the initial velocity of spaceship 1 = u1
6 m/s is the initial velocity of spaceship 2 = u2
and v is the velocity of the 2 ships so that they can collide and combined together
For v we will get the following equation to reach the speed
We can write the law of motion for both trains, calling them train A and train B. Since they both move by uniform motion, so with constant velocity, we can write their position at time t as:
where and are the average speeds of the two trains. For the train B, we put a negative sign, since it is going in the opposite direction.
We want to know the time t after which the distance between the two trains is 50 km. In equations, this means finding the time t after which
And solving, we find:
Which means after 20 minutes.