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Keith_Richards [23]
3 years ago
8

"One step in the manufacture of silicon wafers used in the microelectronics industry is the melt crystallization of silicon into

a crystalline silicon ingot. This processis carried out within a special furnace. When the newly solidified ingot is removed from the furnace, it is assumed to have a uniform initial temperature of 1600 K, which is below the crystallization temperature. At this temperature, the thermal conductivity of silicon is 22 W/(m•K), the density is 2300 kg/m3, and the heat capacity is 1000 J/(kg•K). The hot solid silicon ingot is allowed to cool in air maintained at a constant ambient temperature of 30°C. The diameter of the silicon rod is 15 cm. End effects are considered negligible. The convective heat transfer coefficient is 147 W/(m2•K). What temperature will exist 1.5 cm from the surface of the ingot after a cooling time of 583 sec (9.72 min)?" Consider the rod as acylinder placed vertically.
Physics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

fgfgfdgdg

Explanation:

gfdgfgfgd

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Which of the following have the same density. number 26
marusya05 [52]

1 cubic cm is the same as 1 mL, so the answer would be C.

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NEED AN ANSWER ASAP!
m_a_m_a [10]

Choice-D is the correct statement.

4 0
3 years ago
If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules,
Kitty [74]

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

7 0
3 years ago
Heat transfer between two substances is affected by specific heat and the
IgorLugansk [536]

The correct answer is D. Amount of time and area of physical contact between the substances.

Explanation:

Heat transfer refers to the flow of thermal energy or heat between two or more objects. This process involves multiple factors and implies heat from the hottest object goes to the coldest one until there is an equilibrium. To begin, heat transfer depends on the amount of thermal energy in the objects because objects must have a different amount of thermal energy for heat to flow.

Besides this, the amount of energy that flows depends on the time and the contact between the substances of objects. Indeed, objects need to be in contact or close to each other for heat to transfer, and the time needs to be enough for the process to occur. For example, if you place a pot over the fire just for a few seconds it is likely the heat transferred is minimal, which does not occur if you leave the pot more time. At the same time if the pot is in close contact with fire more heat will be transferred.-

6 0
3 years ago
An object 2.7 cmtall is placed12 cmin front of a mirror. •What type of mirror and what radius of curvature are needed to createa
nasty-shy [4]

Answer:

a. Concave mirror, radius of curvature = 16 cm b. magnification = 2

Explanation:

a. Since the image is upright and larger than the object, we need a concave mirror.

We know image height, h'/object height, h = -image distance, d'/object distance, d

h'/h = -d'/d

Using the real is positive convention,

h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.

So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm

2 = -d'/12

d' = -2 × 12 cm

= -24 cm

Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror

1/+12 + 1/- 24 = 2/r

1/12(1 - 1/2) = 2/r

1/12(1/2) = 2/r

1/24 = 2/r

r/2 = 24

r = 2 × 24

r = 48 cm

b.

magnification = image height, h'/object height,h = + 5.4 cm/+ 2.7 cm = 2

3 0
3 years ago
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