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Setler [38]
3 years ago
12

A large box of mass M is moving on a horizontal floor at speed v0. A small box of mass m is sitting on top of the large box. The

coefficient of static friction between the two boxes is μs and coefficient of kinetic friction between the large box and floor is μk. Find an expression for the shortest distance dmin in which the large box can stop without the small box slipping.
Physics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

dmin = V0^2 / {2(9.8)(μs)}

Explanation:

According to free body diagram, the only forces acting on the small box are force of gravity and force of friction.  

Therefore, the vector sum of the forces in the horizontal direction will be,

ma = F of friction which would be ma = mgμs

a = gμs ……. (1)

Kinematics equation states that, Vf^2 = Vi^2+ 2a (delta d)

Since the large box stops moving, which means Vf = 0 and initial velocity Vi=V0, then kinematics equation becomes

0 = V0^2 + 2a (delta d)

(delta d or dmin) = V0^2/2a …… (2)

 

Substitute the value of a from eqn.1 in eqn. 2, we should get

dmin = V0^2 / {2(9.8)(μs)}

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A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el
GuDViN [60]

Answer:

7.2\cdot 10^{-19} J

Explanation:

The change in electrical potential energy of a charged particle moving through a potential difference is given by

\Delta U = q \Delta V

where

q is the magnitude of the charge of the particle

\Delta V is the potential difference

In this problem:

- the charge of the particle is 3.00 elementary charges, so

q=3e=3\cdot 1.6\cdot 10^{-19} J=4.8\cdot 10^{-19}J

- the potential difference is

\Delta V=4.50 V

So, the change in electrical potential energy is

\Delta U=(1.6\cdot 10^{-19}C)(4.50 V)=7.2\cdot 10^{-19} J

7 0
3 years ago
A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block
mel-nik [20]

Answer:

v₁ = 0.375 m / s ,   x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

       p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

      p_{f} = (m + M) v₁

how the forces are internal

       p₀ =p_{f}

       m v₀ = (m + M) v₁

       v₁ = m /m+M    v₀

let's calculate

       v₁ = 0.4 /(0.4 + 2.8)  3

       v₁ = 0.375 m / s

 

Let's apply Newton's second law to the Block, to find the friction force

Y axis

       N - W = 0

       N = W

       N = m g

where m is the mass of the block

the friction force has the formula

      fr = μ N

      fr = μ m g

We apply Newton's second law to slab    

X axis

       fr = M a

where M is the mass of the slab

       μ m g = M a

       a = μ g m / M

let's calculate

       a = 0.15  9.8  0.4 / 2.8

       a = 0.21 m / s²

With kinematics we can find the position

       v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

       v² = 2 a x

       x = v2 / 2a

let's calculate

        x = 0.375²/2 0.21

        x = 0.335 m

4 0
2 years ago
Explain the law of conservation of energy in your own words .
melamori03 [73]
The law of conservation of energy states that in any reaction, energy cannot be created or destroyed.

In other words, energy has to be conserved in every reaction.
4 0
3 years ago
The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t
marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

I = 9.7 \times 10^{37} kg m^2

Explanation:

Since Earth is considered as solid sphere

So we will have

I = \frac{2}{5}M_eR_e^2

so we will have

I = \frac{2}{5}(5.97 \times 10^{24})(6.371 \times 10^6)^2

so we have

I = 9.7 \times 10^{37} kg m^2

3 0
3 years ago
Order the sounds made by these sources from highest
V125BC [204]

Answer:

c. motorcycle, telephone, piano, lawn mower

Explanation:

3 0
3 years ago
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