
N is the number of leaflets so you just substitute the required number for N.

The cost of printing 2500 leaflets is <span>£</span>7925.
Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
we are given height equation as

where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5

we can solve for h



So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Answer: x =10
Step-by-step explanation:
I'm sorry if its not right
Answer:
C
Step-by-step explanation:
you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.
Answer:
k=10
Step-by-step explanation:
4k + 12= 52
minus 12 on both sides
4k=40
now divide by 4
k=10