By solving a system of equations, we will see that the width is 170ft and the length 275 ft.
<h3>
How to get the dimensions of the base?</h3>
For a rectangle of length x and width y, the perimeter is:
P = 2*(x + y).
Here we know that:
x = 2y - 65ft
p = 890ft = 2(x + y)
So we have a system of equations.
To solve this, we need to replace the first equation into the second one:
890ft = 2(x + y)
890ft = 2(( 2y - 65ft) + y)
Now we can solve this for y.
890ft = 4y - 130ft + 2y
890ft + 130ft = 6y
1020ft/6 = y = 170ft
So the width is 170ft, and we know that:
x = 2y - 65ft = 2*(170ft) - 65ft = 275ft
So the length is 275 ft.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
Step-by-step explanation:boom boom boom boom i want you in my room lets spend the night together
The solution for the expression (v²)(m⁴)/(v²)(m³) will be m. The correct option is C.
<h3>What is an expression?</h3>
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
The given expression will be solved as below:-
E = (v²)(m⁴)/(v²)(m³)
Divide v² by the same term v².
E = (m⁴)/(m³)
E = m
Therefore, the solution for the expression (v²)(m⁴)/(v²)(m³) will be m. The correct option is C.
To know more about expression follow
brainly.com/question/723406
#SPJ1
-1, maybe or maybe not this is my first time doing this
Answer: (C) 0.1591
Step-by-step explanation:
Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with
Let x be the random variable that represents the lifetime of the tires .
z-score : 
For x= 44,500 miles
For x= 48,000 miles
Using the standard normal distribution table , we have
The p-value : 
Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles = 0.1591
