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3 years ago

Unit 3 | Lesson 9

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

D.
20.4 cm
Hope this helps.

Andrei [34K]3 years ago

3 0

P = 6s
s = 3.4

P = 6(3.4) = 20.4 cm

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The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi

Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

$P(X=x)=(_{x}^{n})\ p^xq^{n-x}$

$P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009$

$P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097$

$P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043$

$P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117$

$P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205$

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0

3 years ago

Read 2 more answers

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

4 years ago

What 2 numbers that are the same multiply to be 36 and add up to be 15?

marysya [2.9K]

The only way to have two numbers that are the same and add up to be 15
is if they're both 7.5 , but those don't multiply to be 36. So I guess there's
no answer that satisfies all the conditions of this question.

8 0

4 years ago

PLZ HELP if u know the answer for sure

krok68 [10]

The answer is b (-2 5/6)

6 0

3 years ago

(PERSON WHO ANSWERS WILL BE MARKED BRAINLIEST) Timothy has begun selling copies of his first work of art. In the first year, he

tresset_1 [31]

Y = 40
Since,
1st year = 200
2nd year= 200 + 40 =240
3rd year = 240 + 40 = 280
4th year = 280 + 40 = 320
5th year = 320 + 40 =360
6th year = 360 + 40 = 400.
So, basically all you have to do is add 40!
Therefore, the answer is y = 40 Hope this helped! :)

6 0

3 years ago