Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let
be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
-1(5x+1)
-5x-1
the (-) in front is just a short way to put (-1)
The angles should be included between the equal sides
5530 mm is 553 cm and 5.53 m.

By simplifying this expression it comes down to be
24x-4