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Anestetic [448]
3 years ago
5

Hi I need help I'm clueless and it's due Tomorrow!!!!

Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0
To multiply fractions, multiply the numerators and denominators and reduce if possible. For problem 3, do 7 x 4 = 28. This is the numerator of the answer. The denominator is 8x5 = 40. Therefore, your unreduced fraction is 28/40. Since both 28 and 40 are multiples of 4, you can reduce it to 7/10, since 28/4=7 and 40/4=10.
Use this same process for problems 4 through 12.

For problem 13: 2/5= 4/10, so the black box = 1/2. This is because you multiply the numerators and the denominators.
Numerators: 4 x 1 = 4. Denominators: 5 x 2 = 10
So, your result fraction is 4/10, which reduces to 2/5.
Therefore, the answer is 1/2 ( above math was explanation)

14: multiply the two fractions
6/7 x 4/5 = 24/35, so the answer is 24.

15. Count the shaded squares. There are 25 shaded squares out of 40. The fraction is therefore 25/40 = 5/8.
Now count the dotted squares. There are 24 shaded squares out of 40. The fraction is 24/40= 3/5.
You could also just look at the far right row to get the same answer because it will reduce anyway, but that might confuse you more.

The answer to 15 is multiplying the two fractions, 5/8 x 3/5.

16. Since both fractions reduce to 1 (numerators are the same as denominators), the model would be 3 boxes by 4 boxes, all shaded and all with dots in the middle.
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Lorico [155]

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45

Step-by-step explanation:

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A tank contains 100 gal of brine made by dissolving 80 Ib of salt in water. Pure water runs into the tank at the rate of 4 gal/m
ohaa [14]

Answer:

Step-by-step explanation:

Amount of brine = 100 gal

amount of salt = 80 lb

rate of water running = 4 gal / min

Let A be the amount of salt in lb in the tank at any time t.

(a) dA/dt = rate of salt in - rate of salt out

Rate of salt in = 0

rate of salt out = A x 4 / 100 = A / 25 lb/min

So, dA/dt = 0 - A/25 = - A/25 lb/min

\frac{dA}{A}=-\frac{1}{25}dt

\int \frac{dA}{A}=-\frac{1}{25}\int dt

A(t) = C e^{-0.04t}

When t = 0, A = 80 lb

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A(t) = 80 e^{-0.04t}

(b) Now, A = 40 lb

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40 = 80 e^{-0.04t}

0.5 = e^{-0.04t}

take log on both the sides

ln 0.5 = - 0.04 t

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8 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

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 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

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