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Delicious77 [7]
3 years ago
8

The temperature went from 83 at noon to 72 at midnight. What is the percent of decrease in the temperature from noon to midnight

Mathematics
2 answers:
kiruha [24]3 years ago
7 0
Hello!

(83 - 72) /100 = 9.13

The percent decrease in the temperature was 9.13%°F.

I hope this is correct! :)

(Edit)
bazaltina [42]3 years ago
7 0
It would be 7.92 percent
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Find the regular price. Round to the nearest cent . Sales price is 56.78 percent discount is 40%
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Numerator is 3 and denominator is 5. So, we divide the sales price by 3 and we multiply by 5 to get the whole fraction, or 100%.

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Your regular price sounds recurring, so you might have made a mistake copying.

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REY [17]
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