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Sloan [31]
3 years ago
7

The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when t

he temperature is increased 20k
Chemistry
1 answer:
igomit [66]3 years ago
3 0

Answer:

P_2=20atm

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

Thus, we solve for the final pressure P2 to obtain it as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{10atm*20K}{10K} \\\\P_2=20atm

Hence, we notice that the temperature doubles as well as the pressure.

Best regards.

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