Question

The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when the temperature is increased 20k

Answer 1

Answer:

$P_2=20atm$

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

$\frac{P_1}{T_1}= \frac{P_2}{T_2}$

Thus, we solve for the final pressure P2 to obtain it as shown below:

$P_2=\frac{P_1T_2}{T_1}=\frac{10atm*20K}{10K} \\\\P_2=20atm$

Hence, we notice that the temperature doubles as well as the pressure.

Best regards.