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2 years ago

In the wild, female and juvenile African elephants typically live in herds that vary in size, depending on the

Chemistry

1 answer:

uysha [10]2 years ago

3 0

Herd behavior in elephants ensures that individuals are protected and the species is perpetuated.

<h3>What is her behavior?</h3>

It is a behavior that is characteristic of animals that form herds.

Herds generally refer to groups of animals that live or move together or both.

By protecting individual elephants that are weak or young from being preyed upon by lions and leopards, more members of the population survive.

When more members of the population survive, the species is perpetuated and the likelihood of going into extinction reduces.

More on herd behavior can be found here: brainly.com/question/15112922

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WHAT ARE SOME FUN ALCHSELTER EXPERIMENTS?

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If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is

kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

Data:

P₁ (initial pressure) = 500 torr
V₁ (initial volume) = 0.5 L
P₂ (final pressure) = 700 torr

Wanted:

V₂ (final volume)

Equation:

P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂

Solution:

V₂ = $\frac{(500 torr)(0.5 L)}{700 torr}$ = 0.3571 L or 0.4 L

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2 years ago

The standard emf for the cell using the overall cell reaction below is +2.20 V:

ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

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Reduction: $3I_{2}+6e^{-}\rightarrow 6I^{-}$

---------------------------------------------------------------------------------

Overall: $2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}$

Nernst equation for this cell reaction at $25^{0}\textrm{C}$ -

$E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}$

where n is number of electrons exchanged during cell reaction, $E_{cell}^{0}$ is standard cell emf , $E_{cell}$ is cell emf , $[Al^{3+}]$ is concentration of $Al^{3+}$ and $[Cl^{-}]$ is concentration of $Cl^{-}$

Plug in all the given values in the above equation -

$E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V$

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3 years ago

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Alexus [3.1K]

Answer:

See explanation below

Explanation:

In this case, let's see both molecules per separate:

In the case of SeO₂ the central atom would be the Se. The Se has oxidation states of 2+, and 4+. In this molecule it's working with the 4+, while oxygen is working with the 2- state. Now, how do we know that Se is working with that state?, simply, let's do an equation for it. We know that this molecule has a formal charge of 0, so:

Se = x

O = -2

x + (-2)*2 = 0

x - 4 = 0

x = +4.

Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.

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3 years ago

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