Y=-2x+b
1=-2*(1)+b
1=-2+b
B=1+2=3
Y=-2x+3
2x+y-3=0
We are given: cos theta = 1/3. Thus, adj side = 1 and hyp = 3. Using the Pythagorean Theorem to find the length of the opposite side, represented by x.
1^2 + opp^2 = 3^2, or 1 + x^2 = 9, or x^2 = 8. Here, x could be either sqrt(8) or -sqrt(8): sqrt(8) if angle theta is in QI, and -sqrt(8) if in QIV.
Thus, the sine of angle theta could be either sqrt(8)/3 or -sqrt(8)/3.
The new dimensions of the new rectangle is length 8 inches and width 10 inches.
<h3>How to find width of a rectangle?</h3>
- Perimeter = 26 inches
- Length = 8 inches
- Width = x inches
Perimeter of a rectangle = 2(length + width)
26 = 2(8 + x)
26 = 16 + 2x
26 - 16 = 2x
10 = 2x
x = 10/2
x = 5 inches
New rectangle
= 10 inches
Therefore, the new dimensions of the new rectangle is length 8 inches and width 10 inches.
Learn more about perimeter of rectangle:
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Answer:
Step-by-step explanation: or takes watever numbers you need , for example 5 + 3 or 3 +5 then add and ur done!
Answer:
0.0455
Step-by-step explanation:
<u>The formula for calculator probability is
</u>
# of favorable outcomes / # of possible outcomes
<u>The total number of marbles in the bag: </u>
7+3+2=12
<u>Probability of the first marble being blue:</u>
3/12
<u>Probability of the second marble being blue:</u>
2/11 -- 2 because only 2 blue marbles left after drawing the first one out, 11 because after taking the first marble out, we have 11 marbles left in the bag
<u>Formula for both events happening:</u>
p(A and B) = p(A) * p(B)
In this problem,
A = first one blue
B = second one blue
<u>Probability that if two marbles are drawn out of the bag, both are blue:</u>
3/12 x 2/11 = 0.045454
<u>Rounded answer:</u>
0.0455 (or 4.55%)
