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Leya [2.2K]
3 years ago
14

If (x-4) is a factor of x^2-x-w=0, then the value of w is

Mathematics
2 answers:
Bad White [126]3 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ You have to find a value that, when added to -4, gives -1

This value is +3

The factored form would be (x - 4)(x + 3)

Expand this out:

x^2 + 3x - 4x - 12

==> x^2 -x -12 = 0

w = -12

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

zysi [14]3 years ago
3 0

Step-by-step explanation:

If x-4 is factor, then one value of x is 4

4²-4-w=0

12-w=0

w=12

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F(x) = x² + x ² x ² + x + 2
Oduvanchick [21]

Answer:

y=x^4+x^2+x+2

Step-by-step explanation:

y=x2+x2x2+x+2

y=x4+x2+x+2

Click on picture to get full view!!

if you have any questions let me know!

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8 0
3 years ago
Please please help ! Thank you
miskamm [114]

Answer:

4/3c^4 -it wont let me put it as it shows on your screen but the 4 is on top and under the line is 3c^4,

Step-by-step explanation:

Cancel the common factor of c^3 and z^7 -im not sure if this is what you were trying to get but its a answer-

4 0
3 years ago
What are the coordinates of the vertex of the function f(x) = x2 - 12x + 5?
FinnZ [79.3K]

Answer:

The vertex is the point (6,-31)

Step-by-step explanation:

we have

f(x)=x^2-12x+5

This is a vertical parabola open upward

The vertex represent a minimum

Convert to vertex form

Complete the square

f(x)=(x^2-12x+6^2)+5-6^2

f(x)=(x^2-12x+36)-31

Rewrite as perfect squares

f(x)=(x-6)^2-31 -----> equation in vertex form

therefore

The vertex is the point (6,-31)

6 0
3 years ago
How does Reflection work in real-life situations?
bazaltina [42]

Answer:

reflection is defined as the change in the direction of a wavefront at the interface between two different media, bouncing the wavefront back into the original medium. A common example of reflection is reflected light from a mirror or a still pool of water, but reflection affects other types of waves beside light.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the quadratic function that is created with roots at 2 and 4 and a vertex at (3, 1)?
Arada [10]
Hello,

y=k*(x-2)(x-4)
and is passing throught (3,1)
==>1=k*(3-2)(3-4)==>k=-1

y=-(x-2)(x-4) is an answer
4 0
3 years ago
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