If (x-4) is a factor of x^2-x-w=0, then the value of w is

Mathematics

2 answers:

Bad White [126]3 years ago

6 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ You have to find a value that, when added to -4, gives -1

This value is +3

The factored form would be (x - 4)(x + 3)

Expand this out:

x^2 + 3x - 4x - 12

==> x^2 -x -12 = 0

w = -12

➶ Hope This Helps You!

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zysi [14]3 years ago

3 0

Step-by-step explanation:

If x-4 is factor, then one value of x is 4

4²-4-w=0

12-w=0

w=12

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I need to show work and Idk how for 2 or 3. The -5,-2 and 8,3 is the answers just need work shown thanks

prisoha [69]

#2
2x - 4y = -2
2x + 3y = -16
------------------subtract
-7y = 14
y = 14/-7
y = -2

2x - 4y = -2
2x - 4(-2) = -2
2x + 8 = -2
2x = -2 -8
2x = -10
x = -10/2
x = -5
answer x = -2 and y = -5

check:

2(-5)- 4(-2) = -2
-10 +8 = -2
-2 = -2.....true

2x + 3y = -16
2(-5)+3(-2) = -16
-10 + (-6) = -16
-16 = -16...true

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