It is not a function did I do good
Answer:

Step-by-step explanation:

<u>differentiating numerator wrt x :-</u>
(sinx)' = cos x
<u>differentiating denominator wrt x :- </u>
(1 + cos x)' = (cosx)' = - sinx
- Let's say the denominator was "v" and the numerator was "u"

here,
- since u is the numerator u= sinx and u = cos x
- v(denominator) = 1 + cos x; v' = - sinx


since cos²x + sin²x = 1

diving numerator and denominator by 1 + cos x

For this question, we use the Pythagorean theorem.

We know the lengths of the legs, a and b.


Now, let's solve for the hypotenuse, c.


Take the positive square root.

Hope this helps! :)
Answer:
Step-by-step explanation:
(x + 3)²(x - 5)(x - 8)(x + 7)