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LekaFEV [45]
3 years ago
11

Is this a right triangle?

Mathematics
2 answers:
Sati [7]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

RoseWind [281]3 years ago
3 0

Answer:

It's B.

Step-by-step explanation:

We need to see if AB is perpendicular to BC. If it is then the product of the slopes of BC and AB  will equal -1.

A is the point (-5,5), B is (-3,2) and C is (-6, 0).

Slope of AB = (5 - 2) / (-5 - -3) =  3 / -2 = -3/2.

Slope of BC = (2-0) / (-3 - (-6) = 2 / 3.

The product of their slopes  is -3/2 * 2/3 = -1.

Therefore triangle ABC is right-angled.

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svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

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Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

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Write the equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3
Inga [223]

Answer:

The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:

\mathbf{y=-\frac{2}{3}x+1}

Step-by-step explanation:

We need to write equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3.

The equation for slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We are given slope m = -2/3 and we need to find y-intercept i.e b to write equation of line.

Using point (3,-1) and slope m=-2/3 we can find y-intercept i.e b

y=mx+b\\-1=-\frac{2}{3}(3)+b\\-1=-2+b\\b=-1+2\\b=1

So, y-intercept b = 1

The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:

y=mx+b\\\mathbf{y=-\frac{2}{3}x+1}

7 0
3 years ago
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