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3 years ago

A person has 17 coins, all nickels and dimes, worth $1.25. How many nickels are there?

1 answer:

3 0

This is a problem of guess and check; there's no easier way to do it.But in this case you must have an odd number of nickels to make the 5 cents, so your answer is 9 nickels.you can check this by multiplying each one by .05: 9*.05=.45 the rest of the coins left, are 8 of them, and their dimes. .10*8=.80 .80+.45= 1.25

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Graph Y+5=-2x and explain how you did it.

Margaret [11]

Y
=
−
2
x
+
5
y
=
-
2
x
+
5
Use the slope-intercept form to find the slope and y-intercept.
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Slope:
−
2
-
2
y-intercept:
(
0
,
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(
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Any line can be graphed using two points. Select two
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6 0

2 years ago

Please help asap !!!!!! what vaule of x makes the equation true 3(x-4)=15

DaniilM [7]

3(x-4) = 15

Distribute the 3:

3x-12 = 15

Add 12 to both sides:

3x = 27

Divide both sides by 3:

X = 9

The answer is D. 9

5 0

2 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

Renee uses 12 marshmallows and 8 graham crackers to make 4 s'mores. Drag marshmallows and graham crackers into the box to show h

Anit [1.1K]

To find out how much is needed for 1 you will need to divide each given value by 4:
12 marshmallows / 4 = 3
8 graham crackers / 4 = 2
4 smores / 4 = 1
you then need to multiply each value by 3 :
3 marshmallows x 3 = 9
2 graham crackers x 3 = 6
1 smore x 3 = 3
therefore the answer would be :
9 marshmallows
6 graham crackers

hope this helps you

7 0

3 years ago

Read 2 more answers

If the diameter of the small pizza is 8 inches, what’s the pizza’s area in square inches?

abruzzese [7]

Answer:

Step-by-step explanation: $\pi$ x8x8=201.06192983square inches

7 0

3 years ago

Read 2 more answers