We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.
The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.
The 95% confidence for the population mean will be:
Thus, the 95% confidence interval for the population mean will be (115,123)
So, option A is the correct answer
Answer:
Distance = 45 meters
Time = 3 seconds
Step-by-step explanation:
Here, we want to calculate distance and time
To find the time, we can use one of the Newtons law of motion
V = U + at
In this question
V = final velocity = 18 m/s
U = initial velocity = 12 m/s
a = acceleration
Thus;
18 = 12 + 2(t)
18-12 = 2t
2t = 6
t = 6/2
t = 3 seconds
Mathematically we can also find the distance using one of the equation of motion;
D = ut + 1/2 at^2
D = 12(3) + 1/2 * (2) * 3^2
D = 36 + 9
D = 45 m
Answer:
(-1/2, 1)
Step-by-step explanation:
I just used the midpoint formula, and plugged in the points. I hope this helps!
=(x^2+x^1 /2 , y^2+y^1 /2)
=(-2+1 /2 , -5+3 /2)
=(-1/2, 1)
Answer:
The 95% confidence interval for the population variance is (8.80, 32.45).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:
It is provided that:
<em>n</em> = 20
<em>s</em> = 3.9
Confidence level = 95%
⇒ <em>α</em> = 0.05
Compute the critical values of Chi-square:
*Use a Chi-square table.
Compute the 95% confidence interval for the population variance as follows:
Thus, the 95% confidence interval for the population variance is (8.80, 32.45).
