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3 years ago

Which rule can be used?

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

3 0

Thes first rule is correct.

Another way of doing it is:

Sum the digits of the number. If the result is divisible into nine, then the original number itself will also be.

Example:

18 = 1+8 = 9. 9 is divisible into 9.

27 = 2+7 = 9. 9 is divisible into 9.

Wish you luck!

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Expanding summation

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$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$