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3 years ago

Find the height of a triangle with area 85 1/3 ft squared and base 10 2/3 feet squared

1 answer:

5 0

Lets convert the fractions first:
85 1/3 = 255/3 + 1/3 = 256/3
10 2/3 = 30/3 + 2/3 = 32/3
now, the equation to find the area of a triangle is:
area = height*base/2
so the height is:
height = 2*area/base
then we substitute:
height = 2*(256/3)/(32/3)
= (2*256/3)/(32/3)
= (512/3)/(32/3)
now, dividing by a fraction is the same as multiplying by that fraction upside down:
= (512/3)(3/32)
= (512*3)/(3*32)
= 1536/96
= 16
therefore the height of the triangle is 16 ft

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spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

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Width of cuboid, w = 6 cm

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Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

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Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

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4 years ago

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In a 90 45 45 triangle, the 2 legs each have a
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length = 16 / 1.4142135624 
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erastovalidia [21]

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