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faust18 [17]
2 years ago
14

What is the discriminant of the quadratic equation 3x2 – 3x + 1 = 0?

Mathematics
1 answer:
balandron [24]2 years ago
6 0

Answer:

sqrt(-3)

Step-by-step explanation:

solve using sqrt( b^2 - 4ac)

substitute values from original equation to find discriminant

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How many ink cartridges can you buy with 150 dollars if one cartridge costs 15 dollars ?
musickatia [10]

Answer:

10

Step-by-step explanation:

Very easy equation if you know how to do it. All you need to do is divide your total amount of something (in this case "150" as that's our amount of "money we're given") by whatever the price or amount is. (In this case 15. Each cartridge costs $15. I'm not amazing at explaining things like this.. Sorry about that. If you have any questions about this feel free to let me know!)

So to put it "all together":

150 ÷ 15 = 10.

10 is your answer.

Hope this helps and have a nice day!

8 0
3 years ago
Write the slop intercept form of the equations below.
ohaa [14]
1 is y=1/4x+4
2 is y=x+1
4 0
3 years ago
Read 2 more answers
1. 4x– 15 = 17 - 4x+10x<br> Help?
Nadya [2.5K]

Answer:

x=-16

Step-by-step explanation:

4x– 15 = 17 - 4x+10x

4x+4x-10x = 17+15

-2x=32

-x=16

x=-16

7 0
3 years ago
Mia is standing 210 yd from a radio tower.
Artyom0805 [142]

height = tan(11) x 210

height = 40.81 yards

 rounded to nearest tenth = 40.8 yards

4 0
3 years ago
Read 2 more answers
6. Let f and g be differentiable functions
Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate h(x)=f(x)g(x) we will need the product rule:

h'(x)=f'(x)g(x)+f(x)g'(x).

We have h'(x)=f(x)g'(x), so the following equation is true by the transitive property:

f'(x)g(x)+f(x)g'(x)=f(x)g'(x)

By subtraction property we have:

f'(x)g(x)=0

Since g(x) \neq 0, then we can divide both sides by g(x):

f'(x)=\frac{0}{g(x)}

f'(x)=0

This implies f(x) is constant.

So we have that f(x)=c where c is a real number.

Since f(0)=1 and f(0)=c, then by transitive property 1=c.

So f(x)=1.

Checking:

h(x)=1 \cdot g(x)

h'(x)=g'(x)=1 \cdot g'(x)

So the following conditions were met.

5 0
3 years ago
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