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3 years ago

Find the coordinates of the midpoint of the segment whose endpoint are H(8,13) K(2,1)

Mathematics

1 answer:

sesenic [268]3 years ago

7 0

Answer:(

)

Explanation:

We can find the coordinates of the midpoint of a line segment, by finding the mean of the sum of the

coordinates and the mean of the sum of the

coordinates.

Coordinate of midpoint:

(

)

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A model ship has a mast that is 7 inches tall. A right triangular sail goes from the top of the mast to 1 inch from the bottom o

dezoksy [38]

Answer:

12 square inches.

Step-by-step explanation:

Please consider the complete question.

A model ship has a mast that is 7 inches tall. A right triangular sail goes from the top of the mast to 1 inch from the bottom of the mast. The length of the base of the sail is 4 inches. The height of the sail is along the mast. Find the area of the sail.

The sail will form a right triangle with respect to mast, whose height is 6 inches and base is 4 inches as shown in the diagram.

The area of the sail will be equal to area of triangle.

$\text{Area of triangle}=\frac{1}{2}(\text{Base}\times\text{Height})$

$\text{Area of triangle}=\frac{1}{2}(4\text{ in}\times6 \text{in})$

$\text{Area of triangle}=2\text{ in}\times 6 \text{in})$

$\text{Area of triangle}=12 \text{ in}^2$

Therefore, the area of the sail is 12 square inches.

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3 years ago

Please help will give brainliest if you give proper answer

atroni [7]

On IV the answer is C

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4 years ago

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If (x+5) is a factor of 3x^2+14x+k, what is the value of k?

kherson [118]

If (x+5) is a factor the equation will equal zero when x=-5 so

3(-5^2)+14(-5)+k=0

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4 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

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2 years ago

0.4= Blankx10 please answer quick

Marta_Voda [28]

Answer:

1, 0.4

2, 0.004

3, 0.04

Step-by-step explanation:

hope this helps. :)

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3 years ago

Find the coordinates of the midpoint of the segment whose endpoint are H(8,13) K(2,1)​

Find the coordinates of the midpoint of the segment whose endpoint are H(8,13) K(2,1)