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3 years ago

9

Show all steps necessary to verify the trigonometric identity:

2 answers:

Norma-Jean [14]3 years ago

7 0

All steps are attached in the pic below

vekshin13 years ago

4 0

Answer:

1+tan2x

Tan2x

= <u> sec²x </u> = <u>Sec²x </u> = cosec²x

Tan²x ( Sec²x/cosec²x)

Step-by-step explanation:

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Tom's statement shows a previous balance of $2452.64, a payment of $160, and new transactions $138. what is his new balance if h

elixir [45]

Tom:
Previous balance: 2,452.64
payment: 160
new transaction: 138
APR: 15.6%

We need to divide APR by 12 to get the monthly rate: 15.6% / 12 = 1.3%

2,452.64 - 160 = 2,292.64
2,292.64 * 1.3% = 29.80 interest for the month. We did not include 138 because it still is within the 1 month period and it is not subject to interest. Only the revolving amount of 2,292.64 has interest.
2,292.64 + 29.80 + 138 = 2,460.44 NEW BALANCE OF TOM

Marco:
Unpaid credit card balance: 4,332.75
APR: 18.6%
New transaction: 432

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5 0

3 years ago

What is 6÷(2+4) i really need you to get it right, thx!

lawyer [7]

Answer:

6÷(2+4)= 6÷8= 3/4

........

5 0

3 years ago

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Evaluate the function, find f(-2):<br>f(x) = 2x² + 3x

prisoha [69]

Answer:

2

Step-by-step explanation:

f(-2) = 2(-2)^2 +3(-2)

f(-2)=2

where ever you see x you put -2 there

i hope this helps

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3 years ago

Which of these are accepted as true without proof?

dimulka [17.4K]

Opinions because they are never wrong its just what you think not anyone else

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3 years ago

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

$s = 4$ -- base sides

$V = 36$ -- Volume

<u>Pyramid B</u>

$s = 6$ --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

Read 2 more answers