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Sedbober [7]
2 years ago
9

Show all steps necessary to verify the trigonometric identity:

Mathematics
2 answers:
Norma-Jean [14]2 years ago
7 0

All steps are attached in the pic below

vekshin12 years ago
4 0

Answer:

1+tan2x

Tan2x

=      <u> sec²x  </u>        = <u>Sec²x  </u>       = cosec²x

    Tan²x            ( Sec²x/cosec²x)

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
What is the product when 20 3 is multiplied with 9 25 ?
Novay_Z [31]

Answer:

187.775

Step-by-step explanation:

20.3×9.25=

187.775

4 0
2 years ago
What is the answer to 4|x-1|=12
STatiana [176]

Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12             Divide by 4

  • abs(x - 1) = 12/4            
  • abs(x - 1) = 3                  Equate this to 3
  • x - 1 = 3                          Add 1 to both sides
  • x - 1 + 1 = 3 + 1               Combine
  • x = 4

4*abs(x - 1) = - 12         Divide by 4

  • abs(x - 1) = - 12/4
  • abs(x - 1) = - 3
  • x - 1 = - 3                       Add 1 to both sides
  • x - 1 + 1 = -3 + 1
  • x = - 2

So this has 2 answers

(4,0) and (- 2,0)

5 0
2 years ago
What is the best way to estimate the quotient of 7,713 divided by 18
Effectus [21]

Answer:

Find the number which when divided by 35 gives the quotient 20 and remainder 18.

Step-by-step explanation:

7 0
3 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
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