Answer:
Yes, I like the movie and the musical.
Step-by-step explanation:
I'll be your friend.
To find the maximum height you need to find the vertex:(h,k)
Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height.
k=6 so the kangaroo's maximum height is 6 feet.
To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts.
-.03(x-14)^2+6=0
-.03(x-14)^2+6-6=0-6
-.03(x-14)^2=-6
-.03/-.03(x-14)=-6/-.03
(x-14)^2=200
[(x-14)^2]^.5=200^.5
x-14=(200)^.5
x-14+14=(200)^.5+14
x≈28.14 feet
The kangaroo jumped a distance of 28.14 feet.
You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same.
Step-by-step explanation:
angle AOB = x+3
angle AOC = 2x + 11
angle BOC = 4x-7
angle AOC = angle AOB + angle BOC
=> 2x +11 = (x+3) + (4x-7)
2x +11 = 5x - 4
=> 3x = 15
x = 5
subst x = 5 in the given formulas
angle AOB = x +3 =8
angle AOC = 2x + 11 = 21
angle BOC = 4x - 7 = 13
Answer:
x>2
Step-by-step explanation:
