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2 years ago

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Me. Mesa and Ms. Felipe are going to race each other to see who is going to pay for lunch. Ms. Felipe decides to give Ms. Messa

a ten-foot head start. Ms. Messa runs at a rate of 7ft/s and Ms. Felipe runs at a rate of 9ft/s. Whoever loses gets to pay for lunch.

1 answer:

tia_tia [17]2 years ago

7 0

Answer:

1. y=7x

2. y=9x

Step-by-step explanation:

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2x (y^2+3)-5 (3+y^2)

Irina18 [472]

Use distributive property a(b + c) = ab + ac.

$2x(y^2+3)-5(3+y^2)=(2x)(y^2)+(2x)(3)+(-5)(3)+(-5)(y^2)\\\\=2xy^2+6x-15-5y^2$

3 0

3 years ago

There are five students of different ages. Their median age is 13 years A) what are two possibilities for the ages of the three

Levart [38]

A) the median is the middle measurement. Their ages could be 13, 14 and 15.
B) 2 students must be younger than 13
C) Like I said, the median is the middle measurement. If you have a list of numbers, you have to order them and take the middle number.

:) Have a nice day and maybe consider grading this answer brainliest? <3

6 0

2 years ago

Determine whether or not the triangles below or similar

Anastaziya [24]

Answer:

i think it is D

Step-by-step explanation:

i hope this helped!

p.s it would be cool if you gave me brainliest.

3 0

3 years ago

Use the following function to find f(9)<br> f(x) = 6x<br> f(9)=

san4es73 [151]

Answer:

f(9)=54

Step-by-step explanation:

Subsitute 9 for x in f(x)=6x

$f(9)=6(9)=54$

6 0

2 years ago

Read 2 more answers

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

3 years ago