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NNADVOKAT [17]
3 years ago
6

An activity or a service performed by volunteers free of charge for charge for the benefit of a person group or the public is ca

lled
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
It's litterally called a community service... funny huh?
Helga [31]3 years ago
7 0
Alright give my 1st acc the brainiest award please.
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Is this odd f(x)=X^3-X^2
Oksanka [162]
No it is not I believe
8 0
3 years ago
Read 2 more answers
A. The length side b equals the length of side c
Ann [662]
Shiii it could be answer c
3 0
3 years ago
I will mark you brainlist!
Alborosie

Answer:

B. 4, Heads

4, Tails

5, Heads

5, Tails

6, Heads

6, Tails

Step-by-step explanation:

Given that the cube is labelled 1 to 6 and the coin has a head or a tail, the only outcome when the number cube lands on a number greater than 3 means that the cube lands on 4 or 5 or 6.

On the other hand, the coin may give a head or a tail.

In light of this, the possible answers are;

4, Heads

4, Tails

5, Heads

5, Tails

6, Heads

6, Tails

Hence option B is right

7 0
3 years ago
Given y < 4x – 6, explain how to graph this and decide whether or not (– 1, 5) is a solution to this inequality
svp [43]

the point (-1,5 ) is NOT a solution to the inequality.

There are three steps in graphing an inequality:

Rearrange the equation so "y" is on the left and everything else on the right.

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

Shade above the line for a "greater than" (y> or y≥)

or below the line for a "less than" (y< or y≤).

Now to solve this, graph the line y=4x-6

Lets use the point (0,0)

0<-6, is NOT true

So we shade everything to the left of the line y=4x-6

Hope that helped.

4 0
3 years ago
Las edades de cuatro hermanos forman una progresión aritmética, y su suma es 32 años. El mayor tiene 6 años más que el menor. Ha
Masteriza [31]

Answer:

The ages of the four siblings are: 5, 7, 9 and 11 years old.

Step-by-step explanation:

The computation of the age of the four siblings is shown below:

Given that

n = 4

a1 =? a2 =? a3 =? a4 =?

a4 = a1 + 6 years

S4 = 32

Based on the above information

As we know that

Sn = (a1 + a4) ×  n ÷ 2

S4 = (a1 + a4) × 4 ÷ 2

32 = (a1 + a1 +6) × 2

16 = 2a1 + 6

 2a1 = 10

 a1 = 10 ÷ 2

= 5

So,  a4 = a1 +6

= 5 +6

= 11

a4 = a1 + (4-1) × d

11 = 5 + 3 × d

d = 6 ÷ 3

= 2

So,

a2 = a1 + d

= 5 + 2

= 7

a3 = a2 + d

= 7 + 2

= 9

Hence, The ages of the four siblings are: 5, 7, 9 and 11 years old.

8 0
2 years ago
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