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NNADVOKAT [17]
3 years ago
6

An activity or a service performed by volunteers free of charge for charge for the benefit of a person group or the public is ca

lled
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
It's litterally called a community service... funny huh?
Helga [31]3 years ago
7 0
Alright give my 1st acc the brainiest award please.
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Jessie wants to buy three tickets for a concert. she has earned $135 and each tickey costs $50. she borrows the rest of the mone
dybincka [34]

Answer: In explanation

Step-by-step explanation:

1. 135 - 50x

2. $15

3. $0

I hope this helped!

3 0
1 year ago
What is the solution to this system of equations?
Maurinko [17]

Answer:

  (x, y) = (5, -2)

Step-by-step explanation:

A graphing calculator provides a quick and easy way to find the solution.

_____

There are several other ways to solve these equations. Or you can estimate where the answer might be using logic like this:

The intercepts of the first equation are ...

  • x-intercept = 26/4 = 6 1/2
  • y-intercept = -26/3 = -8 2/3

So the graph of it will form a triangle with the axes in the 4th quadrant.

The intercepts of the second equation are ...

  • x-intercept = 11/3 = 3 2/3
  • y-intercept = 11/2 = 5 1/2

So the graph of it will form a triangle with the axes in the 1st quadrant. The x-intercept of this one is less than the x-intercept of the first equation, so the two lines must cross in the 4th quadrant.

The only 4th-quadrant answer choice is (5, -2).

3 0
3 years ago
. Of the 200 students surveyed in 5th grade, 120 prefer bananas and 80 prefer apples. what is the part to whole ratio?​
kaheart [24]
120:200 prefer bananas, 80:200 prefer apples
7 0
3 years ago
Find the (real-valued) general solution to the differential equation. z′′+5z′=0
andrew-mc [135]
Try this solution:1. to make up the characteristic equation:α²+5α=0;\left[\begin{array}{ccc} \alpha=0 \\ \alpha =-5\\\end{array}2. to make up the final answer:y=C₁+C₂e⁻⁵ˣ
7 0
2 years ago
Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
2 years ago
Read 2 more answers
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