There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
<span>3•(x•y)=(3•x)•y
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answer
associative property of multiplication
Answer:
Step-by-step explanation:
Method 1:
First do the operation inside parenthesis
2*(4-3) = 2*1 = 2
Method 2:
Use distributive property: a*(b +c) = a*b + a*c
2*(4-3) = 2*4 - 2*3
= 8 - 6
= 2
Itś basically the same thing as a compare and contrast circle graph when they intersect with eachother
