Answer:
Yes, B
Step-by-step explanation:
Yes the data is linear because there is a constant rate of change.
For x or the input the rate of change is plus 2
For y or the output the rate of change is plus 4
y/x is your slope so 4/2=2
and the only equation with a slope of 2 is B
8. 1,728 i did 12×18÷2=108×32=345÷2= 1,728
the answer is going to be 6.0
Step-by-step explanation:
1.5 + 1.5 = 3
3 + 3 = 6
I think you forgot to give the options along with this question. Based on my research and knowledge, i am answering the question and hope that the answer comes to your help. Zero correlation is the one that actually describes this situation correctly as "x" and "y" do not have any kind of relationship. I hope the answer comes to your help.
You find the eigenvalues of a matrix A by following these steps:
- Compute the matrix
, where I is the identity matrix (1s on the diagonal, 0s elsewhere) - Compute the determinant of A'
- Set the determinant of A' equal to zero and solve for lambda.
So, in this case, we have
![A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Cimplies%20A%27%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1-%5Clambda%26-2%5C%5C-2%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D)
The determinant of this matrix is
Finally, we have
So, the two eigenvalues are
