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3 years ago

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Mathematics

1 answer:

anygoal [31]3 years ago

6 0

the answer should be the third option

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A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

frosja888 [35]

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.327$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.08, \sigma = \sqrt{1.21} = 1.1$ .

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.327*\frac{1.1}{\sqrt{n}}$

$0.08\sqrt{n} = 2.327*1.1$

$\sqrt{n} = \frac{2.327*1.1}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}$

$n = 1024$

The minimum sample size required to create the specified confidence interval is 1024.

3 0

4 years ago

Please help and explain, I’ll mark you as brainiest

nevsk [136]

Cost
60+20+10+50+25=165
Tax
165*.06=9.90
Cost+Tax
165+9.90=174.90

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3 years ago

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zavuch27 [327]

75% is 3/4
that's all!!
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Molodets [167]

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