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vitfil [10]
4 years ago
14

Francis works in the human resources division of a large oil and gas company in Texas. Francis' tasks include maintaining payrol

l and vacation records, employment histories, and benefit information along with ensuring the security of all sensitive employee information. Which MIS infrastructure is most important to Francis?
Computers and Technology
1 answer:
KiRa [710]4 years ago
4 0

Answer: Information MIS infrastructure

Explanation: Information MIS infrastructure is the company model that is used for supporting the task functioning . The main aim of this tool is to be used in backing -up , plan of diasater recovery and plan of business continuity.

These objectives are achieved by availability, portability , scalability , accessibility, maintainability etc characteristic. Francis is also involved in information MIS infrastructure by maintaining the payroll, records,history of employment  etc, securing the information,etc.

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Importancia del sistema operativo
love history [14]

Answer:

Un sistema operativo es el software más importante de tu computador, ya que se encarga de gestionar el hardware, el acceso a la memoria, acceso a la CPU y controlar gran parte de las tareas que lleva a cabo tu computador.

7 0
2 years ago
_______________ is the term for the convergence of real-time and non-real-time communications services such as telephony, instan
Anna007 [38]

Answer:

Unified communications

Explanation:

Unified communications is the term for the convergence of real-time and non-real-time communications services such as telephony, instant messaging, video conferencing, speech recognition, voice mail, and email into a single interface.

8 0
4 years ago
Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t
GaryK [48]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess  

{

int a,b; //define variable

a=  *(&arr1 + 1) - arr1; //hold length of arr1

b=  *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition  

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

}

return 0; //return value

}

int main() //define main method.

{

   int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

   int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

   cout<< allLess(arr1,arr2); //function calling

   return 0;

}

Output:

1

Explanation:

The Explanation of the C++ language program can be given as follows:

  • In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
  • Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
  • In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
  • In the main method, we define two arrays and pass to the function and use (cout function) for print return value.
8 0
4 years ago
Complete the sentence with the correct response.
Fiesta28 [93]

Answer:

Material systems developer typically combines the skills of a programmer with the multitasking expectations of developing 3 dimensional models of objects, enhancing the graphical effects.

6 0
3 years ago
​Lara is the chief editor of "Laughter and Life," an online magazine. Lara has assigned Jenny the task of redesigning the magazi
Zarrin [17]

Answer:

The "A" option is correct.

Explanation:

For CSS flexbox layout, the property "align-content" requires that the space in the flexbox is more than enough to show the items. In this case, to distribute evenly the items and show the first and last items aligned with the start and end of the main axis, the only suitable option is "space-between". This option leaves no space at the start or at the end of the flexbox, distributing the remaining space between the elements into the flexbox.

7 0
3 years ago
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