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Paladinen [302]
3 years ago
14

Find the value of this expression: sin 45 sin 15 . The second step =

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

Given expression is sin(45)sin(15)

this expression best matches with left side of the formula:

2 sin(A) sin(B)= cos(A-B) - cos(A+B)

so we can plug given angles 45 and 15 there

2 sin(45) sin(15)= cos(45-15) - cos(45+15)

2 sin(45) sin(15)= cos(30) - cos(60)

sin(45) sin(15)= [cos(30) - cos(60)]/2

We are getting negative sign and cos in the solution while none of the given choices have same situation so answer will be none of them.


-----------

For cos(75)-cos(15), we will use formula:

\cos\left(A\right)-\cos\left(B\right)=-2\sin\left(\frac{A+B}{2}\right)\sin\left(\frac{A-B}{2}\right)

Now plug the given angles

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(\frac{75+15}{2}\right)\sin\left(\frac{75-15}{2}\right)

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(\frac{90}{2}\right)\sin\left(\frac{60}{2}\right)

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(45\right)\sin\left30\right)

Hence choice B is correct.

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The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

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10n₃ + 150 + 20n₂ + 50n₃ = 1550

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60n₃ + 150 + 20n₂ = 1550

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expanding the bracket, we have

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collecting like terms, we have

200n₂ + 390 = 1550

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dividing both sides by 200, we have

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Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~

54 * (2/3) = 36 students were on the bus.

54 - 36 = 18 chaperones were on the bus.

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