Answer: Make a chart of x values and corresponding outputs as y-values
Plot the points, draw the curve
Step-by-step explanation: Example of chart
x . y
-1 . 1/9
0 1
1 . 3
2 . 9
3 . 27
Once you do this you will have something similar to graph a or b.
It is difficult to tell from the photo; which graphed curve passes through (2,9) ?
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(x³ - 2)(3x² - 1) + r = 3x⁵ + 3x³ + 2x² + x + 2
x³(3x² - 1) - 2(3x² - 1) + r = 3x⁵ + 3x³ + 2x² + x + 2
x³(3x²) - x³(1) - 2(3x²) + 2(1) + r = 3x⁵ + 3x³ + 2x² + x + 2
3x⁵ - x³ - 6x² + 2 + r = 3x⁵ + 3x³ + 2x² + x + 2
-x³ - 6x² + 2 + r = 3x³ + 2x² + x + 2
-6x² + 2 + r = 4x³ + 2x² + x + 2
2 + r = 4x³ + 8x² + x + 2
r = 4x³ + 8x² + x
Answer: $1000 investment
Step-by-step explanation: