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Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
Answer: The test statistic needed to test this claim= 10.92
Step-by-step explanation:
We know that the probability of giving birth to a boy : p= 0.5
i..e The population proportion of giving birth to a boy = 0.5
As per given , we have
Null hypothesis :
Alternative hypothesis :
Since is right-tailed , so the hypothesis test is a right-tailed z-test.
Also, it is given that , the sample size : n= 291
Sample proportion:
Test statistic : , where n is sample size ,
is sample proportion and p is the population proportion.
i.e. the test statistic needed to test this claim= 10.92
Critical value ( one-tailed) for 0.01 significance level =
Decision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis .
[When test statistic value is greater than the critical value , then we reject the null hypothesis.]
Thus , we concluded that we have enough evidence at 0.01 significance level to support the claim that the YSORT method is effective in increasing the likelihood that a baby will be a boy.