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3 years ago

I really need help on this question, thank you!

Mathematics

1 answer:

bogdanovich [222]3 years ago

6 0

Answer:

Your answer is D

Step-by-step explanation:

When we reflect the point which is at the coordinates (-2,4) we count how far it is from the Y line, it is 2 units away thus we must put our point on the Y line and count 2 to the other side giving us (2,4)

Hope this helps!

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QS and TV are parallel lines

posledela

When referring to crossing lines, adjacent angles means angles which share a vertex and a ray.

The only pair with a common vertex is

VUW and VUR

They share the ray UV as well so they're adjacent angles.

Answer: VUW and VUR

5 0

3 years ago

A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use

Alexandra [31]

Let's assume the cost 20 years ago equals x

3x - 3 = 75

or

x = 75 / 3 + 3

3 0

3 years ago

Read 2 more answers

The graph of an equation is shown below:

ziro4ka [17]

Answer:

The point $(1,3)$ is a solution of the linear equation

Step-by-step explanation:

we have

$A(-3,-2)\ B(1,3)$

Find the equation of the line AB

The slope of the line is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{3+2}{1+3}$

$m=\frac{5}{4}$

Find the equation of the into point-slope form

$y-y1=m(x-x1)$

we have

$m=\frac{5}{4}$

$(x1,y1)=B(1,3)$

substitute

$y-3=\frac{5}{4}(x-1)$

we know that

If a point is a solution to the equation of the line

then

the point must be satisfy the equation and based on the graph the point must be on the line

Let's check every point.

case A) point $(-2,-3)$

Substitute the value of x and y in the equation of the line

$-3-3=\frac{5}{4}(-2-1)$

$-6=-\frac{15}{4}$ -------> is not true

The point $(-2,-3)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

case B) point $(3,1)$

Substitute the value of x and y in the equation of the line

$1-3=\frac{5}{4}(3-1)$

$-2=\frac{10}{4}$ -------> is not true

The point $(3,1)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

case C) point $(1,3)$

Substitute the value of x and y in the equation of the line

$3-3=\frac{5}{4}(1-1)$

$0=0$ -------> is true

The point $(1,3)$ is a solution of the linear equation

See the attached figure-------> the point is on the line

case D) point $(3,2)$

Substitute the value of x and y in the equation of the line

$2-3=\frac{5}{4}(3-1)$

$-1=\frac{10}{4}$ -------> is not true

The point $(3,2)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

8 0

3 years ago

15 14 18 24 10 55 14 19 Find the mean, median and mode

Charra [1.4K]

Answer:

Mean: 21.125

Median: 16.5

Mode: 14

Step-by-step explanation:

First sourt your numbers from smallest to biggest - very important!

Mean= (all numbers total/amount of numbers)=169/8=21.125

Median= The middle two numbers added and divided by two = 15+18/(2)=16.5

Mode=number that appears most often: 14 appears twice!

5 0

4 years ago

Any one please help:)

Leviafan [203]

Answer:

45 total riders

Step-by-step explanation:

Given the equation, t = 5s, where,

t = total riders

s = number of bus-stops

If it picked up 9 bus-stops, to find the total number of riders, substitute s = 9 into the equation.

Thus:

t = 5(9)

t = 45

3 0

3 years ago