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spayn [35]
3 years ago
13

Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper c

ar loader is set to put 84 tons of coal into each car. The actual weights of coal loaded into each car are normally distributed, with mean μ = 84 tons and standard deviation σ = 0.7 ton. (a) What is the probability that one car chosen at random will have less than 83.5 tons of coal? (Round your answer to four decimal places.) (b) What is the probability that 29 cars chosen at random will have a mean load weight x of less than 83.5 tons of coal? (Round your answer to four decimal places.)

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Step-by-step explanation:

this is the answer key for that question and etc...

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Which digit of 7,782 is the hundreds digit?
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(x^2 + 5x + 2) – (5x^2 – x – 2) =
zlopas [31]

Answer:

{ \tt{( {x}^{2} + 5x + 2) - (5 {x}^{2} - x - 2)  }} \\  = { \tt{(1 - 5) {x}^{2}  + (5 + 1)x + (2 + 2)}} \\  = { \tt{ - 4 {x}^{2} + 6x + 4 }} \\  = { \tt{ - 2(2 {x}^{2} - 3x - 2) }}

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Step-by-step explanation:

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Identify the augmented matrix for the system of equations.
lord [1]

Answer:

The augmented matrix for the system of equations is \left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right].

Step-by-step explanation:

This system consists in three equations with three variables (x, y, z).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:

\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]

The augmented matrix for the system of equations is \left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right].

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2 years ago
If u is a unit vector, find u · v and u · w. (assume v and w are also unit vectors.) equilateral triangle
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solution:

we know that ,

u.v = ΙuΙ ΙvΙcosθ

here,

θ =60° (since the given triangle is equilateral triangle)

u.v = ΙuΙ ΙvΙcos60°

     = 1 x 1 x 1/2

u.v = 1/2

now, u.w = ΙuΙ ΙwΙcosθ

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u.w = -1/2


5 0
3 years ago
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