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PIT_PIT [208]
3 years ago
12

Which value of c does not satisfy the inequality 200 − 10c < 150?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0
If c = 4, then <span>200 − 10(4) = 200 - 40 = 160 < 150 (FALSE)
</span>if c = 6, then 200 − 10(6) = 200 - 60 = 140 < 150 (TRUE)
if c = 10, then 200 − 10(10) = 200 - 100 = 100 < 150 (TRUE)
if c = 12, then 200 − 10(12) = 200 - 120 = 80 < 150 (TRUE)

answer
4 does not satisfy <span>the inequality 200 − 10c < 150</span>
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What's equivalent to 2x+3x+8-3x-2? Options arte 2x+6, 2x+10, 5x-3x+6, 5x-3x+10 Select all that are equivalent.
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Read 2 more answers
A survey is being planned to determine the mean amount of time corporation executives watch television. a pilot survey indicated
Natali [406]
Missing question: How many executives should be surveyed?

Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%

Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)

Where N = Sample population

N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554

Therefore, 554 executives should be surveyed to yield such results.
5 0
3 years ago
Use the recursive formula to answer the question. What’s the 7th term in the sequence?
tensa zangetsu [6.8K]

Answer:

a7 = 36

Step-by-step explanation:

Here, we are to use the recursive formula to calculate the 7th term( we add the preceding term to 4 so as to get the succeeding term)

a1 = 12

using the recursive formula given in the question

a2 = 12 + 4 = 16

a3 = 16 + 4 = 20

a4 = 20 + 4 = 24

a5 = 24 + 4 = 28

a6 = 28 + 4 = 32

a7 = 32 + 4 = 36

3 0
3 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
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