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2 answers:
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The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is
To determine the average speed we use the formula,
where and
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
56.4°
Step-by-step explanation:
Let θ = the angle of elevation. Then
tanθ = 199/132 = 1.508
θ = arctan1.508
θ = 56.4°
The angle of elevation is 56.4°.
The distance between 2 points P(a, b) and Q(c,d) is given by the formula:
,
Apply the formula for the points M(6, 16) and Z(-1, 14):
which rounded to the nearest tenth is 7.3 (units)
Answer: 7.3 units
Apply the formula for the points M(6, 16) and Z(-1, 14):
which rounded to the nearest tenth is 7.3 (units)
Answer: 7.3 units