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3 years ago

What is the equation of the line perpendicular to y=1/2x+6 that passes through the point (4, 1)?

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Y = -2x + 9 is your answer!

God bless!

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Write an expression for the length of the rectangle. (Hint: Factor the area binomial and recall that Area=width times length)

cestrela7 [59]

Answer: A=l⋅w where A is the area of the rectangle, l is the length of the rectangle and w is the width of the rectangle.

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2 years ago

Find the length of YZ

emmainna [20.7K]

Larger triangle’s base length

a^2 + b^2 = c^2
a^2 + 3^2 = 8^2
a^2 = 8^2 - (3^2)
sqrt(a^2) = sqrt(55)
a = sqrt(55)
__________________

Smaller triangle’s base length:

The same formula applies.
a^2 + 3^2 = 5^2
a^2 = 5^2 - (3^2)
sqrt(a^2) = sqrt(16)
a = 4
____________

The finale!

Add the two side lengths of a, which is sqrt(55) + 4 (exact answer)
or... 11.416 (unrounded to thousandths place)

Good luck to you!

5 0

2 years ago

PLEASE HELP ME ASAP!<br> Find are and perimeter!!!!

dangina [55]

Area = the top semicircle + the rectangle AEBD

= 1/2 pi*6^2 + 6*12 = 128.55 cm^2 to nearest 100th

Perimeter = 6pi + 12 + 2 pi * 3 = 49.70 cm

6 0

3 years ago

Find area of the shape

pentagon [3]

The answer is a. You find the area of each shape and add them

4 0

2 years ago

I only need 12 and 17, first good response i will give brainliest please i’m desperate

Mumz [18]

Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$