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4 years ago

7

How do I turn "There is a rabbit in the yard" into a sentence without adding any words??

1 answer:

pentagon [3]4 years ago

5 0

Switch the first 2 words.
"Is there a rabbit in the yard?"

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Por favor contesten en a y b

erik [133]

Answer:

what...............

4 0

3 years ago

Urn 1 contains two white balls and one black ball, while urn 2 contains one whiteball and ve black balls. One ball is drawn at r

matrenka [14]

Answer:

4/5 is the probability of white ball from urn 2

Step-by-step explanation:

Correct statement of the question is ;

Urn 1 contains two white balls and one black ball, while urn 2 contains one white bait and five black balls. One ball is drawn at random from urn 1 and placed in urn 2. A ball is then drawn from urn 2. It happens to be white. What is the probability that the transferred ball was white?

We solve it ;

Probability of taking out balls from urn 1

<u>a) for white ball</u>

$P(w_{1} )=\frac{2}{3}$

<u>b) for balck ball</u>

$P(b_{1} )= \frac{1}{3}$

If one ball is taken from urn 1 and put in urn 2 (which readily contains one white and five black balls)

Probability of taking out balls from urn 2

<u>a) for white ball</u>

$P(w_{2} )=P(\frac{w_{2} }{w_{1} } ).P(w_{1} )+P(\frac{w_{2} }{b_{1} } ).P(b_{1} )$

$=\frac{2}{7} . \frac{2}{3} + \frac{1}{7}. \frac{1}{3} =\frac{5}{21}$

Then the probability that white ball was transferred from urn 1 to urn 2 is;

$P(\frac{white ball transfer }{w_{2} } )= \frac{P(\frac{w_{2} }{w_{1} } ).P(w_{2} )}{P(w_{2}) }$

$=\frac{ \frac{2}{7}.\frac{2}{3} }{\frac{5}{21} }$

$=\frac{4}{5}$

So, the probability that white ball is drawn from urn 2 is 4/5

4 0

3 years ago

Each year three space shuttles are launched, two in June and one in October. If each shuttle is known to occur without a delay i

Veronika [31]

Answer:

0.271 or 27.10%

Step-by-step explanation:

If the present month is January, in 16 months there will be three space shuttles launched (two in June and one in October).

The probability that at least one launch will be delayed is 100% minus the probability that no launch will be delayed:

$P(delay>0) = 1 - P(delay=0)\\P(delay>0) = 1 -0.90^3\\P(delay>0) = 0.271$

The probability that at least one of the launches in the next 16 months will be delayed is 0.271 or 27.10%.

4 0

3 years ago

-4/3 divided by 12/5

Ksivusya [100]

Answer:

-5/9

Step-by-step explanation:

−4/5 divided by 12 /5

=-20/36

simplify

=-5/9

5 0

3 years ago

Read 2 more answers

Write two expressions where the solution is 30

mel-nik [20]

Answer:

(15+0)2

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers