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4 years ago

How do I turn "There is a rabbit in the yard" into a sentence without adding any words??

Mathematics

1 answer:

pentagon [3]4 years ago

5 0

Switch the first 2 words.
"Is there a rabbit in the yard?"

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The enrollment at Sonya's school is 109% of last years enrollment. What decimal represents this year's enrollment to last year's

Dominik [7]

1.09 because all percents are divided by 100 to find the decimal

4 0

3 years ago

Read 2 more answers

Part 1) A school is selling tickets to a play. Tickets cost $12 at the door and $8.50 if purchased in advance. The school has a

Tems11 [23]

Answer:

See below

Step-by-step explanation:

Given:

Tickets cost $12 at the door, number of tickets d
Tickets cost $8.50 if purchased in advance, number of tickets a
Minimum target from tickets sold $1050

Required inequality to meet the goal:

12d + 8.5a ≥ 1050

If a = 36 then minimum value of d:

12d + 36*8.5 ≥ 1050
12d + 306 ≥ 1050
12d ≥ 1050 - 306
12d ≥ 744
d ≥ 744/12
d ≥ 62

Minimum 62 tickets must sell

6 0

3 years ago

The temperature in Frostport is 8°F and dropping at a rate of 3.5 degrees per hour. How many hours will it be until the temperat

faust18 [17]

8-3.5t=-20

8

Mark brainliest please

8 0

3 years ago

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

4 years ago

How do you do do dod

slavikrds [6]

Answer:

I don't know!

Step-by-step explanation:

4 0

3 years ago